先化简,再求值:(1-x/x+2)·(x2-4/x2-2x+1)÷(1/x2-1)其中x2-x=0.
1个回答
原式=-(x-1)/(x+2)*(x+2)(x-2)/(x-1)²*(x²-1)
=-(x-2)/(x-1)*(x+1)(x-1)
=-(x-2)(x+1)
=-(x²-x-2)
=-(0-2)
=2
相关问题
先化简,再求值:(x−1x2−1+1x+1)÷4x2+x,其中x=-2.
先化简,再求值:(1-[1/x])÷x2−2x+1x2−1,其中x=2.
先化简再求值先化简再求值:(x-x/x+1)(x+1/x^2+4x+4)(x^2-4/x^2-2x),其中x=-0.5
(1)先化简,再求值:(1−1x)÷x2−2x+1x2−1,其中x=2.
先化简,再求值:x2−1x2+2x+1÷x−1x2+x,其中x=2013.
先化简,再求值:(1+3x−1)÷x2−4x2−2x+1,其中x=3.
先化简,再求值:(x2+4x−4)÷x2−4x2+2x,其中x=-1.
先化简,再求值:(x−1x−x−2x+1)÷2x2−xx2+2x+1,其中x满足x2-x-1=0.
先化简,再求值:x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2,其中x=根号2
先化简,再求值(3x+4x2−1+21−x)÷x+2x2−2x+1,其中x=4.