Question

CaC2O4在PH=3.0HCL溶液中的溶解度

Answer 1

溶解时生成的是H2C2O4

Ka=Ka1*Ka2=3.776*10^-12

[H+]^2*[C2O42-]

---------------=Ka (1)

[H2C2O4]

[Ca2+]*[C2O42-]=Ksp (2)

[H+]=10^-3 (3)

[Ca2+]=.=[C2O42-]+[H2C2O4]

CaC2O4+2H+====Ca2++H2C2O4

K=[Ca2+][H2C2O4]/[H+]^2=[Ca2+][C2O42-]/Ka=Ksp/Ka

可以求出[Ca2+],再换算成溶解度