Question

2x³-6x+4这个一元三次方程怎么解

Answer 1

2x^3-6x+4=0

x^3-3x+2=0

x^3-x-2x+2=0

x(x^2-1)-2(x-1)=0

x(x-1)(x+1)-2(x-1)=0

(x-1)[x(x+1)-2]=0

(x-1)(x^2+x-2)=0

(x-1)(x+2)(x-1)=0

(x+2)(x-1)^2=0

x=-2 或 x=1