Question

已知abc不等于0 且a+b+c不等于0 且c/(a+b)=a/(b+c)=b/(a+c)=k,则反比例函数y=（k-1

Answer 1

∵abc不等于0 且a+b+c不等于0

c/(a+b)=a/(b+c)=b/(a+c)

由等比性质,得

(a+b+c)/(2a+2b+2c)=k

∴k=(a+b+c)/(2a+2b+2c)

=(a+b+c)/[2(a+b+c)]

=½

∴k-1=½-1=-½

则反比例函数y=（k-1）/x的图像经过【第二、四】象限.