由(x+2/3)²+|y-1|=0得:
x+2/3=0 ①x= -2/3
y-1=0 ②y=1
则:1/2*x-2(x-1/3*y²)+(1/3*y²-3/2*x)
=(1/2-2-3/2)x+(2/3+1/3)y²
=y²-3x
代入得:原式=y²-3x=1²-3*(-2/3)=3
由(x+2/3)²+|y-1|=0得:
x+2/3=0 ①x= -2/3
y-1=0 ②y=1
则:1/2*x-2(x-1/3*y²)+(1/3*y²-3/2*x)
=(1/2-2-3/2)x+(2/3+1/3)y²
=y²-3x
代入得:原式=y²-3x=1²-3*(-2/3)=3