Question

1/(m^2-m)+(m-5)/(2m^2-2) 分式计算

Answer 1

1/(m^2-m)+(m-5)/(2m^2-2)

=1/[m(m-1)]+(m-5)/[2(m+1)(m-1)]

=2(m+1)/[2m(m+1)(m-1)]+m(m-5)/[2m(m+1)(m-1)]

=[2(m+1)+m(m-5)]/[2m(m+1)(m-1)]

=(m²-3m+2)/[2m(m+1)(m-1)]

=(m-1)(m-2)/[2m(m+1)(m-1)]

=(m-2)/[2m(m+1)]