[(x+2y)²-(x+y)(3x-y)-5y²]÷2x
=[x²+4xy+4y²-(3x²-xy+3xy-y²)-5y²]÷2x
=[x²+4xy+4y²-3x²+xy-3xy+y²-5y²]÷2x
=[-2x²+2xy]÷2x
=-x+y