(I)设等差数列{a n}的公差为d
∵a 7=4,a 19=2a 9,
∴
a 1 +6d=4
a 1 +18d=2( a 1 +8d)
解得,a 1=1,d=
1
2
∴ a n =1+
1
2 (n-1) =
1+n
2
(II)∵ b n =
1
n a n =
2
n(n+1) =
2
n -
2
n+1
∴s n= 2(1-
1
2 +
1
2 -
1
3 +…+
1
n -
1
n+1 )
= 2(1-
1
n+1 ) =
2n
n+1
(I)设等差数列{a n}的公差为d
∵a 7=4,a 19=2a 9,
∴
a 1 +6d=4
a 1 +18d=2( a 1 +8d)
解得,a 1=1,d=
1
2
∴ a n =1+
1
2 (n-1) =
1+n
2
(II)∵ b n =
1
n a n =
2
n(n+1) =
2
n -
2
n+1
∴s n= 2(1-
1
2 +
1
2 -
1
3 +…+
1
n -
1
n+1 )
= 2(1-
1
n+1 ) =
2n
n+1