(1)
AB = √2 - 1
|x - 0| = |x| = √2 - 1
x = √2 - 1
或
x = 1 - √2
(2)原式表示BC²
(a) x = √2 - 1 > 0,
BC = √2 - (√2 - 1) = 1
原式 = 1
(b) x = 1 - √2
(1)
AB = √2 - 1
|x - 0| = |x| = √2 - 1
x = √2 - 1
或
x = 1 - √2
(2)原式表示BC²
(a) x = √2 - 1 > 0,
BC = √2 - (√2 - 1) = 1
原式 = 1
(b) x = 1 - √2