Question

求一道微积分题的解答∫dx/[x^根号下(a^+x^)]^表示平方 根号下的是（a^+x^) 不好意思不会用搜狗打符号,

Answer 1

∫ dx/[x^2√(x^2+a^2)]

=∫ dx/[x^3√(1+(a/x)^2)]

=∫-1/2*d(1/x^2)*[1/√(1+(a/x)^2)]

=∫-1/(2a^2)*d(a/x)^2*[1/√(1+(a/x)^2)]

=-1/(2a^2)∫d[(a/x)^2+1]/√(1+(a/x)^2)]

= -1/a^2 *√[(a/x)^2+1]

= -1/a^2 * √(a^2+x^2)/x + C

令：x=atant , a/x = cott , sint=√csct^2=1/√[(a/x)^2+1]

∫ dx/[x^2√(x^2+a^2)]

=∫ asect^2 dt/[a^2tant^2 asect]

=∫ sect dt/[a^2tant^2]

=1/a^2∫ cost/ t^2 dt

=1/a^2∫ 1/sint^2 dsint

=1/a^2 [-1/sint] + C

= -1/a^2 * √(a^2+x^2)/x + C