若x、y、z是正整数,又(x-y)(x+y)=7,x和y各等于几
1个回答
(x-y)(x+y)=7
x+y=7
x-y=1
x=4,y=3
相关问题
X= Y+Z的7分之2,Y=X+Z的8分之3 X,Y,Z各等于几,X:Y:Z=?
若X+2y+3z=9求正整数X,y,z
已知x、y、z是正整数,求解下列联立方程 (x-y)(y-z)(z+x)=-90 (x-y)(y+z)(z-x)=42
x+y+z等于53 x+y+y等于51x+x+y等于48请问x y z各等于
若x,y为正整数,且满足3x(x+y)-y(x+y)=7,求x,y
若整数n可表示为n=(x+y+z)[(x-y)²+(x-z)²+(y-z)²]/2(x、y
若整数x,y,z,w满足x>y>z
若整数x,y,z,w满足x>y>z
x,y,z和n都是正整数,n^x+n^y=n^z.
x+y+z=15 x+5y+10z=70 x,y,z,各是几?