已知函数f(x)=(√3)sin²x+sinxcosx-(√3)/2;(1)若x∈(0,π/2),求函数f(x)的最大值;(2)在三角形ABC中,若AA;故2B-π/3=π-π/6=5π/6,2B=5π/6+π/3=7π/6,故B=7π/12;
于是C=π-(A+B)=π-(π/4+7π/12)=π-5π/6=π/6.
已知函数f(x)=(√3)sin²x+sinxcosx-(√3)/2;(1)若x∈(0,π/2),求函数f(x)的最大值;(2)在三角形ABC中,若AA;故2B-π/3=π-π/6=5π/6,2B=5π/6+π/3=7π/6,故B=7π/12;
于是C=π-(A+B)=π-(π/4+7π/12)=π-5π/6=π/6.