1)移项:(x-2)/(x+1)>0 等效于:(x-2)(x+1)>0 所以:{x|x>2或x0 化为:x2-2x-15>=0 (x-5)(x+3)>=0 解得:x>=5
(2) 当x=0 (x+5)(x-3)>=0 解得:x=5或x