(高数)求y=e^(-x)cos(3-x)的微分

1个回答

  • 微分的乘积法则和链式法则学过吗?这两个都是微分基本的法则,做这道题时都会用到.

    y=e^(-x)cos(3-x)

    dy/dx = {d[e^(-x)]/dx}cos(3-x) + e^(-x){d[cos(3-x)]/dx}(乘积法则)

    = -e^(-x)cos(3-x) + e^(-x)(-1)(-sin(3-x))(链式法则)

    = e^(-x)[-cos(3-x)+sin(3-x)]