Question

x∧12－1在整数范围内因式分解

Answer 1

=（x^6+1）(x^6-1)

=(x²+1)(x⁴-x²+1)(x²-1)(x⁴+x²+1)

=(x²+1)(x⁴-x²+1)(x+1)(x-1)【(x⁴+2x²+1)-x²】

=(x+1)(x-1)(x²+1)(x⁴-x²+1)[(x²+1)²-x²]

=(x+1)(x-1)(x²+1)(x⁴-x²+1)(x²+x+1)(x²-x+1)