Question

1.a、b互为相反数,c、d互为倒数,求（a+b-1）+cd的值 2.若|a+1|+|b+2|+|c+3|=0,求abc

Answer 1

1.a、b互为相反数,c、d互为倒数,求（a+b-1）+cd的值

（a+b-1）+cd

=(0-1)+1=0

2.若|a+1|+|b+2|+|c+3|=0,求abc的值

a+1=0

b+2=0

c+3=0

abc=(-1)*(-2)*(-3)= -6