室温下,在强酸性和强碱性溶液中都不能大量共存的离子组是?(请写下原理)

3个回答

  • 题目有错.除非不考虑选项中混合溶液自身反应 C中应该是Cl-吧?

    A.本身不共存,H+ + HCO3- = CO2↑ + H20 NH4+ + HCO3- + H2O= NH3H2O + H2CO3

    B.本身不共存.Al3+ + 3NH3H2O = Al(OH)3↓ + 3NH4+

    C.在强碱下可共存,强酸下不共存 SO32- + 2H+ = H2SO3

    D.强酸下不共存,强碱下可共存 CH3COO- + H+ =CH3COOH OH- CO32- + 2H+ =H2CO3 OH- + H+ = H2O

    无法选

    如果不考虑选项中混合溶液自身反应

    A.强酸强碱下均不共存.NH4+ + OH- = NH3H2O,H+ +OH- =H2O HCO3- + H+ =CO2↑ + H20 HCO3- + OH- = CO32- + H2O

    B.强酸强碱下均不共存.Al3+ + 4OH- = Al02- + 2H20 NH3H2O + H+ = NH4+ +H20

    C.在强碱下可共存,强酸下不共存 SO32- + 2H+ = H2SO3

    D.强酸下不共存,强碱下可共存 CH3COO- + H+ =CH3COOH OH- CO32- + 2H+ =H2CO3 OH- + H+ = H2O