解二元一次方程组一.30²+(60x)²=(75x)²二.(X-50)【800-20(X-

1个回答

  • 原式=900+3600x²=5625x² 900=2025x² x²=36/81

    【∵36=±6x(±6) 81=±9x(±9)】∴ x=±(6/9)

    原式=(X-50)[800-20(X-60)]=12000

    (X-50)[800-20(X-50-10)]=12000

    800X(x-50)-20(x-50)²+200(x-50)=12000

    -20(x-50)²+1000(x-50)-12000=0

    (x-50)²-50(x-50)+600=0

    (x-50-30)(x-50-20)=0

    x=80 或x=70

    原式=X²=(X+1)²-(X-1)² X²=(X+1-X+1)(X+1+X-1) X²=4X X²-4X=0 X(X-4)=0

    X=4或X=0

    原式=π【(4/9)X(0.5X)²-(0.5x-3)²】=0 【∵4/9 = 2X2/(3X3)】

    ∴π【(2/3)²X(0.5X)²-(0.5x-3)²】=0

    πX(2/3 -0.5x+3 )X(0.5X-0.5x+3)X(2/3 +0.5x-3 )X(0.5X+0.5x-3)=0

    πX3X(11/3)X(0.5x-7/3)X(x-3)=0

    11π(0.5x²-23/6x+7)=0

    11π{0.5【x²-23/3x+(23/3)²】+7-529/18}=0

    11π【0.5(x-23/3)²-403/18】=0

    0.5(x-23/3)²-403/18=0

    0.5(x-23/3)²=403/18

    x=23/3±根号403/3=(23±根号403)/3

    话说第四题我不能确定