cos(α-π/2)*tan(-α-3π/2)*s

cos(α-π/2)*tan(-α-3π/2)*sec(-α+5π/2)*tan(α+5π/2)

1个回答

已知：f(α)＝sin(π2−α)•cos(3π2−α)•tan(5π+α)tan(−α−π)•sin(α−3π)
化简：sin2(α+π)•cos(π+α)tan(π+α)•cos3(−α−π)•tan(−α−2π)．
tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就
化简 [Sin(π+α)\tan(π+α)] ×[ cot(2π-α)\cos(π+α)]×[sec(2π-α)\csc
已知f(α)＝sin(α−π2)cos(3π2−α)tan(2π−α)tan(−α−π)sin(π+α)．
化简：（1）tan(π−α)•sin2(α+π2)•cos(2π−α)cos3(−π−α)•tan(α−2π)；（2）s
化简：sin²（α+π)cos(-α+π)/tan(α+π)tan(α+2π)cos²(-α-π)
已知f（α）=sin2(π−α)•cos(2π−α)•tan(−π+α)sin(−π+α)•tan(−α+3π)．
已知f(α)＝sin2(π−α)•cos(2π−α)•tan(−π+α)sin(π+α)•tan(−α+3π)，
化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)