Question

现有两个不同的char型变量,取值为年月（yyyymm）,要写一个循环取出他们之间的取值,例如：char1 = ‘201

Answer 1

基本上是用C写的,子函数改下try..catch那部分,就可以用C编译了.

生成的字符串是用空格分开的,单个使用的话用strtok就行了.

#include

#include

#include

using namespace std;

char* getInnerDate(char *char1,char *char2)

{

char *p1,*p2,*sRet,*pRet;

int yy1,mm1,yy2,mm2,mm,m,y;

char buff[10];

// Swap date string order.

if( strcmp(char2,char1) >= 0){

p1 = char1;

p2 = char2;

}else{

p1 = char2;

p2 = char1;

}

// Translate to year & month.

try{

strncpy(buff,p1,6);

buff[6] = 0;

mm1 = atoi(&buff[4]);

buff[4] = 0;

yy1 = atoi(buff);

strncpy(buff,p2,6);

buff[6] = 0;

mm2 = atoi(&buff[4]);

buff[4] = 0;

yy2 = atoi(buff);

}catch(...){

return NULL;

}

// Total months between 2 date strings.

mm2 += (yy2 - yy1) * 12 + 1;

sRet = (char*)malloc((mm2*7 + 1)*sizeof(char));

if(NULL != sRet){

pRet = sRet;

y = yy1;

m = mm1;

for(int mm=mm1; mm 12){

m -= 12;

y ++;

}

sprintf(pRet,"%04d%02d ",y,m);

m++;

pRet += 7;

}

}

return sRet;

}

int main(void)

{

char char1[]="201110",char2[]="201203";

char *p;

if(NULL != (p = getInnerDate(char1,char2))){

cout