3x²-[2x²y-(2xyz-x²z)-4x²z]-2xyz
=3x²-(2x²y-2xyz+x²z-4x²z)-2xyz
=3x²-(2x²y-2xyz-3x²z)-2xyz
=3x²-2x²y+2xyz+3x²z-2xyz
=3x²-2x²y+3x²z
=x²(3-2y+3z)
=(-2)²*[3-2*(-3)+3*1]
=4*(3+6+3)
=4*12
=48
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3x²-[2x²y-(2xyz-x²z)-4x²z]-2xyz
=3x²-(2x²y-2xyz+x²z-4x²z)-2xyz
=3x²-(2x²y-2xyz-3x²z)-2xyz
=3x²-2x²y+2xyz+3x²z-2xyz
=3x²-2x²y+3x²z
=x²(3-2y+3z)
=(-2)²*[3-2*(-3)+3*1]
=4*(3+6+3)
=4*12
=48
*这是乘号
请首先关注【我的采纳率】
请及时点击【采纳为最佳回答】按钮~