Question

x的平方加xy加y的平方等于27,求x

Answer 1

x^2+xy+y^2-27=0

X1=[-Y+√(Y^2-4Y^2+108)]/2

=[-Y+√(108-3Y^2)]/2

X1=[-Y+√3√(36-Y^2)]/2 (1)

X2=[-Y-√(108-3Y^2)]/2

=-[Y+√3√(36-Y^2)]/2 (2)

(1)(2)为本问题的解,为了得到实数解,Y