Question

函数f(x)=根号下(x^2-2x+1)+2根号下（4-4x+x^2)

Answer 1

1

f(x)=√(x^2-2x+1)+2√(4-4x+x^2)=|x-1|+2|x-2|

x-2≥0 时f(x)=3x-5 f(x)≥1

x-1≤0 f(x)=5-3x f(x)≥2

1