4m^2(m+n)-9n^2(m+n)
1个回答
解由4m^2(m+n)-9n^2(m+n)
=(m+n)(4m^2-9n^2)
=(m+n)(2m-3n)(2m+3n)
相关问题
4(m+n)^2-9(n-m)^2
(m^2-6mn+9n^2)/(3n-m)-(4m^2-9n^2)/(2m-3n) m=-2 n=2008.化简求值
① 4(m+2n)²-9(2n-m)² 因式分解
若(m-2n)/(2m+n)=3,则[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)] - {9(m-2n
(m+2n)-6(m+2n)(2m-n)+9(n-2m) 因式分解
(m+2n)^2-6(m+2n)(2m-n)+9(n-2m)^2 因式分解
(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)-(2m-3n)怎么做
(m+n)2+6(m2-n2)+9(m-n)2.
(m+n)2+6(m2-n2)+9(m-n)2.
因式分解 9(2m+n)²-4(m-2n)平方