1.1/(n*(n+1))=1/n*1/(n+1)=1/n-1/(n+1);
理由的话你可以反推啊,先通分再消掉式子就可以了.
2.1/(x-2)*1/(x-3)-2/(x-1)*(x-3)+1/(x-1)(x-2)
=1/(x-3)-1/(x-2)-2/(x-1)*(x-3)+1/(x-2)-1/(x-1)
=1/(x-3)-1/(x-1)-2/(x-1)*(x-3)
=2/(x-3)*(x-1)-2/(x-1)*(x-3)
=0
1.1/(n*(n+1))=1/n*1/(n+1)=1/n-1/(n+1);
理由的话你可以反推啊,先通分再消掉式子就可以了.
2.1/(x-2)*1/(x-3)-2/(x-1)*(x-3)+1/(x-1)(x-2)
=1/(x-3)-1/(x-2)-2/(x-1)*(x-3)+1/(x-2)-1/(x-1)
=1/(x-3)-1/(x-1)-2/(x-1)*(x-3)
=2/(x-3)*(x-1)-2/(x-1)*(x-3)
=0