Question

已知ab互为倒数,xy互为相反数,/m/=2,求(x+y)×a÷b+m

Answer 1

ab互为倒数,a÷b=1xy互为相反数x+y=1|m|=2 m=±2(x+y)×a÷b+m=1*1+m=±23x^2+my-8-(nx^2+2y+7)=(3-n)x^2+(m-2)y-15不含有x,y,所以3-n=0 m-2=0 n=3 m=2n^m+m^n=2^3+3^2=8+9=17...