已知（4x+3)/x=0,求分式（2x-x^2)/ - 知识问答

已知（4x+3)/x=0,求分式（2x-x^2)/(x^3+x^2)*(x^2+2x+1）/x^2-4x+4)的值.

2个回答

4+3/x=0
x=-3/4
(2x-x^2)/(x^3+x^2)*(x^2+2x+1)/(x^2-4x+4)
=[x(2-x)/x²(x+1)]*[(x+1)²/(x-2)²]
=[11/(-3)]*[1/(-11)²]
=-1/33

相关问题