Question

求一简单的曲线方程题求方程（x+y-1)√x-y-2=0的曲线注：√是根号

Answer 1

（x+y-1)√x-y-2=0

等价于x+y-1=0或x-y-2=0且x-y-2≥0

联立x+y-1=0与x-y-2=0

x=3/2

所以轨迹为直线x-y-2=0和射线x+y-1=0（x≥3/2)