Question

解x的平方-6x+8分之2x的平方-10x+1小于等于1

Answer 1

(2x²-10x+1)/(x²-6x+8)≤1

(2x²-10x+1)/(x²-6x+8) -1≤0

[(2x²-10x+1)-(x²-6x+8)]/(x²-6x+8)≤0

(x²-4x-7)/(x²-6x+8)≤0

(x²-4x+4-11)/(x²-6x+8)≤0

[(x-2)²-11]/(x²-6x+8)≤0

[x-(2-√11)][x-(2+√11)]/[(x-2)(x-4)]≤0

4