Question

1/(x^2-x)+1/(x^2-3x+2)=3/(2x-x^2)解分式方程,

Answer 1

1/x(x-1)+1/(x-2)(x-1)=-3/x(x-2)

乘以公因式：x(x-1)(x-2)

（x-2)+x(x-1)=-3(x-1)

x^2-5+3x=0

(x+3/2)^2=29/4

x1=（根号下29 -3）/2

x2= -(根号下29 +3)/2