Question

函数f(x)=√[2-(x+3)/(x+1)]的定义域为A,g(x)=lg[(x-a-1)(2a-x)](a

Answer 1

f(x)=√[2-(x+3)/(x+1)]的定义域为A,g(x)=lg[(x-a-1)(2a-x)](a0,或者x-1≤0且x+10且2a-x>0,或者x-a-1a+1,所以2a>a+1

所以x2a不成立

所以x>a+1且x