Question

已知直线l的方程为xsina-根号3y+2=0,则l的倾斜角的取值范围是

Answer 1

xsina-√3y+2=0

y=√3*sina *x/3+2√3/3

设l的倾斜角为α

tanα=√3*sina /3

-1≤sina≤1

则 -√3/3≤tanα≤√3/3

则 {α|5π/6≤α≤π} ∪｛α| 0≤α≤π/6}