(1)f(x)=sin²x-sin(2x-π/6)=(1-cos2x)/2-(sin2xcosπ/6-cos2xsinπ/6)
=1/2-(cos2x)/2-sin2xcosπ/6+(cos2x)/2=1/2-sin2xcosπ/6
所以f(x)的值域为【1/2-根号3/2,1/2+根号3/2】;
(2)条件不全
(1)f(x)=sin²x-sin(2x-π/6)=(1-cos2x)/2-(sin2xcosπ/6-cos2xsinπ/6)
=1/2-(cos2x)/2-sin2xcosπ/6+(cos2x)/2=1/2-sin2xcosπ/6
所以f(x)的值域为【1/2-根号3/2,1/2+根号3/2】;
(2)条件不全