若2x+5y+4z=6,3x+y-7z=—4,求x+y-z
1个回答
一式各乘以3减掉二式乘以2,得到y+2z=2,
二式乘以5减掉一式,得到x-3z=-2,
x+y-z=0
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已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
求文档: 若2x+5y+4z=6,3x+y-7y=-5,求x+y+z的值?
(1)2X+4Y+3Z=93X-2Y+5Z=115X-6Y+7Z=13(2)X:Y=3:2Y:Z=5:4X+Y+Z=66
若2x+5y+4z=6,3x+y-7z=-4,那么x+y-z的值是多少?
若2x+5y+4z=6,3x+y-7z=-4,那么x+y-z的值是多少?
3x+7y+z=5 ,4x+10y+z=6 ,x+y+z=