对数式 运算过程写下哈,1.(lg5)²+2lg2-(lg2)²=?2.lg〖(根号下3+根号5)+(根号下3-根号5)

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  • (lg5)²+2lg2-(lg2)²

    =(1-lg2)^2+2lg2-(lg2)²

    =1-2lg2+(lg2)²+2lg2-(lg2)²

    =1

    lg[根号下(3+根号5)+根号下(3-根号5)]=

    [3+5^(1/2)]^(1/2)+[3-5^(1/2)]^(1/2)

    ={{[3+5^(1/2)]^(1/2)+[3-5^(1/2)]^(1/2)}^2}^(1/2)

    ={3+5^(1/2)+3-5^(1/2)+2*[4^(1/2)]}^(1/2)

    =10^(1/2) 所以,

    原式=lg[10^(1/2)]=1/2

    log(2)5=log(3)5/log(3)2

    log(5)3=log(3)3/log(3)5=1/log(3)5

    log(2)25乘log(3)4乘log(5)9

    =(2*log(2)5)(2*log(3)2)(2*log(5)3)

    =8*log(3)5*log(5)3

    =8*log(3)5*1/log(3)5

    =8