Question

第十题求过程高三数学

Answer 1

y^2=2px的焦点F(p/2,0),直线x-my+m=0过F,则有p/2+m=0,p=-2m直线方程代入到抛物线上有y^2=2p(my-m)=-4m(my-m),即有y^2+4m^2y-4m^2=0y1+y2=-4m^2,y1y2=-4m^2|y1-y2|^2=(y1+y2)^2-4y1y2=16m^4+16m^2S(OAB)=1/2OF*|y1-y2...