Question

若x,y为实数,且y=(根号（2x+1/3-4x))+(根号（2x+1/4x-3))+1,求x+yx+x^2y的值

Answer 1

y=(根号（))+(根号（2x+1/4x-3))+1

2x+1/3-4x=-(2x+1)/(4x-3)>=0

2x+1/4x-3>=0

3-4x≠0

∴2x+1=0

x=-1/2

得y=1

x+yx+x的平方*2y

=-1/2-1/2+1/4*2=-1/2