用三次洛必达法则：(x-xcosx)'=1-cox+xsinx (x-sinx)'=1-cosx
(1-cox+xsinx)'=2sinx+xcosx (1-cosx)'=sinx
(2sinx+xcosx)'=3cosx-xsinx (sinx)'=-cosx
lim(x→0)(x-xcosx)/(x-sinx)=lim(x→0)(3cosx-xsinx)/-cosx=-3
求 lim(x→0) （x-xcosx）/（x-sinx）,
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