Question

不定积分 c / 根号x的dx我求解过程 (c为常数)

Answer 1

∫(c/√x)dx

=c∫[x^(-1/2)]dx

=c*x^(-1/2+1)/(-1/2+1)+C

=c*x^(1/2)/(1/2)+C

=2c√x+C,(C为未定常数)

∴∫(25/√x)dx

=2*25√x+C,(代入上面的结果)

=50√x+C