m(BaCO3)=14.51g-4.66g=9.85g
m(BaSO4)= 4.66g n(BaCO3)= 9.85g÷197g/mol=0.05mol
n(BaSO4)= 4.66g÷233g/mol=0.02mol
m(Na2SO4) = 2.84 g
V(CO2)= 0.05mol×22.4L/mol=1.12L
m(BaCO3)=14.51g-4.66g=9.85g
m(BaSO4)= 4.66g n(BaCO3)= 9.85g÷197g/mol=0.05mol
n(BaSO4)= 4.66g÷233g/mol=0.02mol
m(Na2SO4) = 2.84 g
V(CO2)= 0.05mol×22.4L/mol=1.12L