Question

(1)x^2*x^8+x^13/x^3 (2)a^19/a^12/a^3 (3) (x-2y)^5/(2y-x)^3 (

Answer 1

x^2*x^8+x^13/x^3

=x^(2+8)+x^(13-3)

=x^10+x^10

=2x^10

a^19/a^12/a^3

=a^(19-12-3)

=a^4

(x-2y)^5/(2y-x)^3

=[-(2y-x)]^5 / (2y-x)^3

=-(2y-x)^(5-3)

=-(2y-x)^2

(x-y)^5/(x-y)

=(x-y)^(5-1)

=(x-y)^4

(x-y)^6/(y-x)^4

=(x-y)^6 / (x-y)^4

=(x-y)^(6-4)

=(x-y)^2