Question

已知甲乙的面积差是25平方厘米,ABCD是正方形,边长是15厘米,求正方形EFGC的边长.

Answer 1

SRT△ADH-SRT△GCH=25,

设正方形EFGC的边长为X,

连接AC,

SRT△ADH+S△ACH=S正方形ABCD/2

S△ACH=15x15/2-SRT△ADH,

SRT△ACH+S△GCH=15X/2

15x15/2-SRT△ADH+S△GCH=15X/2

15X/2=15x15/2-(SRT△ADH-S△GCH)

15X/2=15x15/2-25

X=35/3(厘米)