Question

已知式子3x²-4x+6的值为9,则x²-4/3×x+6的值为?

Answer 1

x²-4/3×x+6=(x²-4/3×x+6)*3/3=[(3x²-4x+6)+12]/3=21/3

,A=3x²-2x+1 +B C=B-4+2x³ A-C=3x²-2x+1 +B -B+4-2x³ =-2x³+3x²-2x+5