X＝(√3－√2)÷(√3﹢√2)
=（√3-√2）²/[(√3+√2)(√3-√2)]
=5-2√6
Y＝(√3＋√2)÷(√3－√2)
=(√3+√2)²/[(√3-√2)(√3+√2)]
=5+2√6
3X²－5XY＋3Y²
=3(x²-2xy+y²)+xy
=3(x-y)²+xy
=3×(5-2√6-5-2√6)²+(5-2√6)(5+2√6)
=3×96+25-24
=289
X＝(√3－√2)÷(√3﹢√2),Y＝(√3＋√2)÷(√3－√2),求3X²－5XY＋3Y²的值
2个回答
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