设船到岸边的距离为x,绳子长度为L
根据勾股定理,x^2+1=L^2
等号两边同时关于t求导
得2x*dx/dt=2L*dL/dt
已知dL/dt=1.1,x=8
可以求出L=sqrt(65)
所以16dx/dt=2sqrt(65)*1.1
解得dx/dt=1.109
错了不要抽我.
And do realize that if you asking this online is against school rules I will not be responsible.
设船到岸边的距离为x,绳子长度为L
根据勾股定理,x^2+1=L^2
等号两边同时关于t求导
得2x*dx/dt=2L*dL/dt
已知dL/dt=1.1,x=8
可以求出L=sqrt(65)
所以16dx/dt=2sqrt(65)*1.1
解得dx/dt=1.109
错了不要抽我.
And do realize that if you asking this online is against school rules I will not be responsible.