已知a/sinA=3 则a+b+c/sinA+sinB+sinC=
1个回答
a/sinA =b/sinB=c/sinC
由等比定理得,(a+b+c)/(sinA+sinB+sinC)=3
相关问题
已知a/sinA=2,则a+b+c/sinA+sinB+sinC=?
a/sinA=b/sinB=c/sinC (a+b+c)/(sinA+sinB+sinC)=a/sinA'''''为什么
设a/sinA=b/sinB=c/sinc=k则sinA=a/k,sinB= ,sinC=
在△ABC中,已知(sinA+sinB+sinC)(sinA+sinB-sinC)=3,a
△ABC中,a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=______.
△ABC中,a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=______.
△ABC中,a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=______.
在△ABC中,已知sinA*sinB*cosC=sinA*sinC*cosB+sinB*sinC*cosA,若a,b,c
如何证明a/sinA=b/sinB=c/sinC=(a+b)/(sinA+sinB)
数学中有a/sinA=b/sinB=c/sinC=(a+b+c)/sinA+sinB+sinC这个公式吗