1.
(x-1)(x-1-2)=0
x=1或3
2.
(x+2+3)(x+2-3)=0
x=-5或1
3.
9(x-2)²-4(x+1)²=0
[3(x-2)+2(x+1)][3(x-2)-2(x+1)=0
(5x-4)(x-8)=0
x=4/5或8
4.
2(t-1)²+t-1=0
(t-1)[2(t-1)+1]=0
(t-1)(2t-1)=0
t=1或1/2
用因式分解法解方程 （1） （x-1)²-2（x-1)=0
1.
(x-1)(x-1-2)=0
x=1或3
2.
(x+2+3)(x+2-3)=0
x=-5或1
3.
9(x-2)²-4(x+1)²=0
[3(x-2)+2(x+1)][3(x-2)-2(x+1)=0
(5x-4)(x-8)=0
x=4/5或8
4.
2(t-1)²+t-1=0
(t-1)[2(t-1)+1]=0
(t-1)(2t-1)=0
t=1或1/2