首先保证真数为正,有x+2>0且x²-x-6>0,联立解得
x>3
由log3(x+2)-log3(x²-x-6)+1>0变形得
log3(x+2)-log3[(x-3)(x+2)]>-1
log3{(x+2)/[(x-3)(x+2)]}> log3(1/3)
log3[1/(x-3)]> log3(1/3)
1/(x-3)>1/...
首先保证真数为正,有x+2>0且x²-x-6>0,联立解得
x>3
由log3(x+2)-log3(x²-x-6)+1>0变形得
log3(x+2)-log3[(x-3)(x+2)]>-1
log3{(x+2)/[(x-3)(x+2)]}> log3(1/3)
log3[1/(x-3)]> log3(1/3)
1/(x-3)>1/...