1/1X3+1/3X5+1/5x7+1/7+9+…+1/49x51=?
2个回答
1/1X3+1/3X5+1/5x7+1/7+9+…+1/49x51
=1/2*(1-1/3+1/3-1/5+1/5-1/7+...+1/49-1/51)
=1/2*(1-1/51)
=25/51
相关问题
1X3分之1+3X5分之1+5X7分之1+……49X51分之1
1/1*3+1/3*5+1/5*7+1/7*9+.+1/49*51
1/1x3+1/3x5+1/5x7+1/7x9+1/9x11+1/11x13=
1X1/3+3X1/5+5X1/7+7X1/9+.+99X1/101=?
求简便计算:3.51X49+35.1X5.1+49X5.1
3.51x49+35.1x5.1+49x51用简更方法计算
x-4/1+9=10/9x 怎么算?还有:49x+51*(x-7)=81*100 (x-25)+(1-5%)(325-x
x-([1/3]+[2/3])=[7/12] 2x+[7/9]=[7/9] 15x-4.5×2=51 7x+3x+26=
1/3X1/5=1/15=(1/3-1/5)X1/2,1/5X1/7=1/35=(1/5-1/7)X1/2,1/7X1/
1/1×3+1/3×5+1/5×7+1/7×9+……+1/49×51