Question

(4x-1)÷3-(x-2)÷6=(4+x)÷2 怎么解

Answer 1

（1）(4x-1)÷3-(x-2)÷6=(4+x)÷2

2(4x-1)-(x-2)=3(4+x)

8x-2-x+2=12+3x

4x=12

x=3

（2）x/3-x/5=4

5x-3x=60

2x=60

x=30

(3)(y+2)÷4-(y-3)÷5=10

5(y+2)-4(y-3)=200

5y+10-4y+12=200

y=178